WampServer

Thanks! Post Edited (08-01-06 20:01)
Forum: WampServer English

Develop in asp or perl
Forum: WampServer English

Also, should the following code work: I've missed out the ?. <php if ($_POST['PASSWORD'] == 'password') { php> <p>If the conditional satement is true then this is printed</p> <php } php>
Forum: WampServer English

Still no joy. I don't think the problem is with the code as the follow code also does nothing: echo "it works" Help please!!!
Forum: WampServer English

Right... I've just downloaded WAMP5 and created a relation. Here is the intension: ITEMTYPE(ItemType/char(50)). Pretty simple huh? I made one entry to the table. Here is the index page: <?php $qry = "select * from ITEMTYPE"; $recordset = mysql_query($qry) or die( "query failed" $row = mysql_fetch_array($recordset) or die( "fetch failed" e
Forum: WampServer English