WampServer

Hi everybody I have a problem using $_POST on my wamp

I until recently uploaded all my code to a FTP to a professional hosting company server. It was great for my needs.

Then I heard about wamp, and it seems to be a almost perfect solution. But it seems that my offline code had some problems using $_POST. When I tried to call print_r($_POST); it was totally empyt, while online it was correctly filled..

Now, what do I do, to make it work? I expect it to be something in the .ini file, but i'm not sure.. Please have in mind that I do not have that much experience yet.

btw, the search on this site doesn't seem to work for me?

print_r($_POST);


this isnt not correct php

u need a varaible???



anyway proper way to write this is

$xxxx=$_POST['xxxx']'
print_r($xxxx);



fill in xxxx as yout variable being posted

I am sorry to inform you that it does work, on my offline version $_POST is empty, on my online version the $_POST contains the info that is needed.

code:
echo "<pre>";
print_r($_POST);
echo "</pre>";

result - offline:
Array
(
)

result- online:
Array
(
[username] => admin
[password] => password
[loginremem] => on
)

well its wrong.

you need to use $_POST with a variable..

you should not just assume it will know wat to print.


paste up both form and php script.

The script works fine, its running on proffesional paid for company servers, with no problems at all.

The problem is that my WAMP server does not give the $_POST variables to the script.

You have to enable Output_Buffering in php.ini file in apache/bin directory.

im not saying your way of doing things wont work.. but u dont do it unless you wanna justcheck the array being past.



there is no problem with $_POST on wamp

there is a prolem with your script


so post the whole thing up if you want it checked

no output buffering is enabled by default on wamp, jixar just post the script up if you want it checked.
dont mind that it works on other server



Edited 1 time(s). Last edit at 03/03/2008 12:09AM by stevenmartin99.

stevenmartin99 => I do not want it checked. I'm not saying wamp is buggy either. I belive it is a simple server setting that does the trick. I have checked and double checked, even with the solution you suggested (print_r($_POST['xxx'])

Following line returns a false, and displays the default error for empty pass/user:
Validator::login($_POST['username'], $_POST['password']);

Inside the code there are several checks wehter the pass/user is either empty, or invalid (' OR ''='' is invalid ;-) ) They return a false on the local, because the variables are empy. While online the script works fine.

- Now, please take your eyes of the code.

hambuler => output_buffering = on

It doesn't do the trick?



Edited 1 time(s). Last edit at 03/03/2008 12:19AM by Jixar.

people on this site looking for help get more rude every day..


if your POSTING A VARIABLE WITH THE NAME password TO A PHP SCRIPT


AND YOU HAVE


<?php
$password=$POST['password'];

echo $password;
?>


IT HAS TO WORK
THERE IS NO "LITTLE SETTING" TO MAKE IT WORK
YOUR CODE IS WRONG..

I forget to tell you you have to enable register_globals in apach2/bin php.ini file. It's not advisable to leave it on forever.

this was taken out of php5.2 for a reason...

register_globals = on
No effect

And stevemarting99, no need to write in caps, nobody is rude

Remember that we're all trying to solve the problem.


Is it possible that local settings for Javascript might do the difference? I'm using Firefox..

Relevant JS code + html:

function loginFormSubmit(sentForm)
{
if(sentForm.loginremem.checked&&!loginFormUnTouched)
setLoginCookie(sentForm.username.value,sentForm.password.value);
document.cookie="logget=true;expires=";
sentForm.submit();
}

<form name="loginform" style="padding:0px;margin:0px;" action="<?php echo $url->setVar("action", "logon"; ?>" method="post">
<?php $url->remVar("action"; ?>
<input type="text" name="username" style="width:120px;" onKeyDown="loginTouched()"><br>
<input type="password" name="password" style="width:100px;margin-top:4px;margin-bottom:4px;" onKeyDown="loginTouched()"><br>
<input type="checkbox" name="loginremem" onClick="if(this.checked){if(!confirm('Vil du have computeren til at huske dit login næste gang du kommer på?')){this.checked=false}}">Husk mig<br>
<input type="button" name="loginbutton" value="Login" onClick="loginFormSubmit(this.form)"><br>
</form>

action="<?php echo $url->setVar("action", "logon"; ?>"



wat is this?


do you have another script? that prints them


cos it shoud be
action='otherscrotname.php'


your no even passing the variables onto the oter page thats why they are blank

Quote:
register_globals = on
No effect
****************

Have you restarted the apache server?

hambuler => Server was restarded, 3 times to make sure
Remote server is running globals off.

Stevemartin99 => its my URL object, the method setVar($keyword, $value); adds and returns an url ex:

$url = new URL("forum.wampserver.com/read.php";
$url->setVar("action", "logon"; //forum.wampserver.com/read.php?action=logon

If you use it again, it adds even more

$url->setVar("thread", "1258"; //forum.wampserver.com/read.php?action=logon&thread=1258

Its how I controll the links on the entire page



Edited 1 time(s). Last edit at 03/03/2008 12:51AM by Jixar.

if its in the url


u need to use GET not POST

The variables from the forms are in POST.

The action defines where you are taken when you submitted the login

action='index.php?action=logon' method='POST'

^takes you to 'index.php?action=logon' with both GET and POST's

It does work this page uses it to make sure you land on the english site when submitting.

Jixar
I know you don't like to post the whole codes since it's a little personal, but it would not help if you keep post piece by piece. If you really like to get your problem solve, you might edit to replace all personal info and post your whole script so people can help you out
BTW, mots hosting services out there are *nix which might have a little different settings compare w/ wamp, so if your scripts run perfectly on your host service, ask your host's tech what need to be done in order for you to test your script on local wamp (Apache, MySQL, and PHP run on Windows)

Have fun,

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The code is not that personal, its shared by 4 students i study with, its just a bit complex.. I have simplified it a bit here then:

SIMPLE index.php:

<?php
	
	include_once("core/core.php"; //Class files, db connection, etc.
	//Also includes ActionHandler.php!
	
	include_once("plugin/PluginHandler.php"; //Plugin handling, decides what page to show.

//Design is added...

	echo Menu::writeUserMenu();	//This static method adds the menu for the current user, this is where the problems are...

//More design

?>

SIMPLE Menu class:

<?php 
	$currentUser = new CurrentUser();	//This class tells the script who the user is, userlevel, id, name and the most important, is he logged in??

	if($currentUser->isOnline()){ //Is the user logged in the system.
		//Design and the menu for the user.
	}else{
	?>
		<fieldset style="padding:5px;">
		<legend>Login her&nbsp;</legend>									
			<form name="loginform" style="padding:0px;margin:0px;" action="<?php echo $url->setVar("action", "logon"; ?>" method="post">
																		<?php $url->remVar("action"; ?>
			<input type="text" name="username" style="width:120px;" onKeyDown="loginTouched()"><br>
			<input type="password" name="password" style="width:100px;margin-top:4px;margin-bottom:4px;" onKeyDown="loginTouched()"><br>
			<input type="checkbox" name="loginremem" onClick="if(this.checked){if(!confirm('DO you want the computer to remember you next time you enter the page?')){this.checked=false}}">Cookie <br>
			<input type="button" name="loginbutton" value="Login" onClick="loginFormSubmit(this.form)"><br>
			</form>
		</fieldset>
	<?php 		
	}

SIMPLE ActionHandler.php

<?php
	$action = $_GET['action'];
	if($action == "logon"{	//Brugeren forsøges logget ind
		Validator::login($_POST['username'], $_POST['password']);	//Logs user in, return bool and mutate a class that writes a message for the user in the design.
		
		$currentURL = new CurrentURL();	//Contains the URL of the current page, contained in arrays.
		$currentURL->remVar("action";
		Validator::redirect($currentURL->getUrl());	//A redirect function, since the actionhandler is included in core.php, it can be done via header.
	}
?>

Javascript for loginForm:

function loginFormSubmit(sentForm)
{
	if(sentForm.loginremem.checked&&!loginFormUnTouched)
		setLoginCookie(sentForm.username.value,sentForm.password.value);
	document.cookie="logget=true;expires=";
	sentForm.submit();
}

SIMPLE class Validator

<?php
	public static function login($username, $password){
		if(($legal) && (!isset($password))){$legal = false;}
		if(($legal) && (!isset($username))){$legal = false;}
		if(($legal) && (!Validator::validUsername($username))){$legal = false;}
		if(($legal) && (!Validator::validPassword($password))){$legal = false;}
		if($legal){
			$encryptedPass = Validator::spicyPassword($password);	//Add a salt and encrypt
		}

		if($legal){	//User exists?
			$num_usernamesPasswords = DB::sqlNum("SELECT id FROM users WHERE username='$username' AND password='$encryptedPass'";
			if($num_usernamesPasswords != 1){
				$legal = false;
			}
		}
			//Log user in
			//Return true.
		//If user not logged in return false
	}
}
?>

I can't see where the code should be wrong. Everything with login except the forms, happen before headers are sent to the user.

It uses $_POST to login and nothing fancy beyond that.
The javascript simply places a cookie on the machine and submits the form.

EDIT: Typo's and ekstra text



Edited 2 time(s). Last edit at 03/03/2008 09:23AM by Jixar.